Ecuaciones+Lineales

Ecuaciones Lineales


 * Una Solución
 * [[image:una_solucion.png]]
 * Sin Solución
 * [[image:2_soluciones.jpg]]
 * Infinita
 * [[image:infinitO.jpg]]

Métodos para resolver ecuaciones cuadráticas Suma y resta



Sustitución



Igualación



Determinantes



Gráfica



Deber # 1  Resolución de ecuaciones

1. Nadia Paredes ej
ej 1 ej 2 2. Daniela Terán ej 687, 729



3. Julio Vela





4. Dominic Yaucan





5. Diana Mena

  <span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;">

<span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;"> <span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;">6. Lizett Gallardo

<span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;">

<span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;"> <span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;">7 Carolina Galarza

<span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;"> <span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; line-height: 0px; overflow: hidden;">

<span style="display: block; font-family: 'Arial Black',Gadget,sans-serif;">8. Alejandro Moreno





FIN Daniela Terán













Carolina Galarza

912.- X + 4 - 7 – X = 4 X + 7 -1 3 X-3 9

3 ( x + 4 ) ( x – 3 ) - ( 9 ) ( 7 – x ) = (4x + 7) ( x – 3 ) - ( x – 3 ) ( 9 ) ( 3x + 12 ) ( x – 3 ) – 63 + 9x = 4x ² - 12 x + 7x – 21 – 9x + 27 3x² - 9x + 12x – 36 – 63 + 9x = 4x² -12x + 7x - 21-9x + 27 3x² + 12x – 99 = 4x² - 14x + 6x 0 = x² - 26x + 105 ( x – 21 ) ( 8x – 5 ) = 0 X = 21 x = 5.

913.- X + 30X ˉ¹ = 5

X + 30= 5 5 X X² + 150 = 25X X² - 25X + 15 = 0 ( X -1 0 ) ( X - 15) X = 10 X =15

914.-

1/3 / X/3 = 1 – X/1 / 3X + 1/3 1 ( 3X + 1 ) = ( 6X ) ( 3 – 3X ) 9X² - 9X + 3X +1 = 0 9X² - 6X + 1 = 0

X = 6± (6)²-4(9)(1) <span style="display: block; height: 5px; left: 26px; position: absolute; top: -1px; width: 104px; z-index: 251663872;"> 18 X = 1/3

944.- √3x-6 + √2x+6 = √9x+4

(√3x - 6 + √2x + 6)² = (√9x + 4)² 3x -6 + 2 √3x-6 √2x + 6 + 2x + 6 = 9x + 4 5x + 2 √3x-6 √2x + 6 = 9x + 4 2 √6x² + 1 8x -12x = 4x + 4 (√6x² + 6x – 36)² = (2x+2)² 2x ² - 2x – 40 = 0 x² - x – 20 = 0 (x - 5)(x - 4) = 0 X = 5 X = -4

934.- (√3 - √3 + √ X - √ 2X + 1)² = (1)² 3- √3 + √ X - √ 2X + 1 = 1 (2)² = (√3 + √ X - √ 2X + 1)² (1)²= (√ X - √ 2X+1) ² 1 = X – √ 2X + 1 2X + 1 = X² - 2X + 1 0 = X² - 4X + 0 X = 4 ± √ 4² -4 2 X= 4 X= 1/2

<span style="border-bottom: windowtext 1pt solid; border-left: windowtext 1pt solid; border-right: windowtext 1pt solid; border-top: windowtext 1pt solid; display: block; padding-bottom: 1pt; padding-left: 4pt; padding-right: 4pt; padding-top: 1pt;">

<span style="display: block; padding-bottom: 0in; padding-left: 0in; padding-right: 0in; padding-top: 0in; text-align: center;">** Corrección de la Prueba ** Fecha: 2010 – 09 – 29 · Transformar las siguientes expresiones en suma de os radicales. 1.- √-15y – 8y√1 a = -15y a² = 225y² b = √ -64y² b = -64y² √ A² - B = √ 225y² + 64y² = √289 y² ; 17y. √15y + 17y / 2 - √15y – 17y / 2 √32y / 2 - √-2/2y √16y - √ y 4√y - √ y.

Julio Vela



<span style="display: block; font-family: 'Arial Black',Gadget,sans-serif; font-size: 26px; line-height: 0px;">